Réponses

2013-03-10T18:53:51+01:00

3y(y-1)-3y²(-2y+2) = 3y²-3y+6y^3-6y²= 6y^3 - 3y²-3y = y(6y² - 3y - 3)

 

(x-3)(3x-2) + ( x-1)(8+2x) = 3x² - 2x -9x + 6 + 8x + 2x² - 8 - 2x = 5x² - 5x - 2 = x(5x - 5 ) - 2

 

(-3x-5)(x-4) - ( 2x-2)(x+3) = -3x² + 12x - 5x + 20 - 2x² - 6x + 2x + 6 = -5x² + 3x + 26 =  x ( -5x+3) + 26