Réponses

2012-12-01T21:09:44+01:00

y' = (-1/2)[(2t³+1)³(t+3)]^(-3/2) . [3(2t³+1)².(6t²).(t+3) + (2t³+1)³]

  = (-1/2)[(2t³+1)³(t+3)]^(-3/2).[(2t³+1)²(18t²(t+3) + 2t³+1)]

  = (-1/2)[(2t³+1)³(t+3)]^(-3/2)(2t³+1)²(20t³ + 54t² + 1)