Réponses

2014-06-03T19:40:12+02:00
A = x² - 16       (identité remarquable)
A = (x+4)(x-4)

B = 1 - y²
B = (1+y)(1-y)

C = 100x² - 9
C = (10x+3)(10x-3)

D = 36 - 81z²
D = (9z+6)(9z-6)

E = 4π² - 25
E = (2π+5)(2π-5)

F = (t+3)² - 16    
F = ((t+3)+4)((t+3)-4)

G = (2x+1)² - 25
G = ((2x+1)+5)((2x+1)-5)

H = (3i+7)² - (i+5)²
H = ((3i+7)+(i+5))((3i+7)-(i+5))

Meilleure réponse !
  • Utilisateur Brainly
2014-06-03T19:45:26+02:00
A = (x-4)(x+4)

B =(1-y)(1+y)

C =(10x-3)(10x+3)

D =(6-9z)(6+9z)

E =(2pi-5)(2pi+5)

F = (t+3-4)(t+3+4)
   = (t-1)(t+7)

G = (2x+1-5)(2x+1+5)
   = (2x-4)(2x+6)
   = 4(x-2)(x+3)

H = (3i+7-i-5)(3i+7+i+5)
   = (2i+2)(4i+12)
  on peut encore facto mais je pense que tu dois t'arreter là




je finis : H = (3i+7-i-5)(3i+7+i+5)
= (2i+2)(4i+12)
on peut encore facto 4(i+1)(2i+6)