Réponses

2012-11-19T11:02:19+01:00

Cm(x)=(1/3x^3-1/4x²-1/2x+2)/x=x²/3-1/4x-1/2+2/x

Donc Cm'(x)=2/3x-1/4-2/x²=(2x)/3- (1/4) -(2/x²)=( (4x²*2x)-3x²-(2*12))/12x²=(8x^3-3x²-24)/12x²=f(x)/12x²