Réponses

2014-02-24T12:42:21+01:00
Soit N(x;y) BN = (× -2;y) ; AB=(6;-1) ; NA= (-4-×; 1 - y) -3 (×-2;y) +(12;-1) - 2 (-4-×; 1-y) = (-3×+6+12+8+2× ; -3y-1-2+2y)=(0; 0) (-× + 26;-y - 3) = (0; 0) -× + 26 = 0 => ×=26 -y-3 = 0 => y= -3 N= (26;-3)