Réponses

2012-10-23T19:57:19+02:00

5(x-3)² = 3(x+2)(x-3)

5(x-3)² - 3(x+2)(x-3) = 0

(x-3)(5x - 15 - 3x - 6) = 0

(x-3)(2x - 21) = 0


donc 2 solutions :

x = 3

ou

x = 21/2


En espérant t'avoir aidé.

2012-10-23T20:06:09+02:00

 5(x-3)² = 3(x+2)(x-3) = 5(x-3)²- 3(x+2)(x-3) =0

 5(x-3)(x-3)- 3(x+2)(x-3) =0

(x-3)(5x-15-3x-6)=0

(x-3)(2x-21)=0 si x-3=0 x=3  et si 2x-21=0 x=21/2

S(3;21/2)

bonne chance