Réponses

Meilleure réponse !
  • Utilisateur Brainly
2013-12-23T10:41:19+01:00
forme factorisée
f(x)=(x+1/3)²-4(x-1/3)²
=(x+1/3)²-(2x-2/3)²
=(x+1/3+2x-2/3)(x+1/3-2x+2/3)
=(3x-1/3)(-x+1)


forme développée
f(x)=(x+1/3)²-4(x-1/3)²
=x²+2x/3+1/9-4x²+8x/3-4/9
=-3x²+10x/3-1/3

forme canonique
f(x)=(x+1/3)²-4(x-1/3)²
=-3x²+10x/3-1/3
=-3(x²-10x/9)-1/3
=-3((x-5/9)²-25/81)-1/3
=-3(x-5/9)²+25/27-1/3
=-3(x-5/9)²+16/27
=-3((x-5/9)²-16/81)