Réponses

2013-12-21T21:53:52+01:00
Bonsoir

(x² - 3x)(x + 1) + 2x(x - 3) - 2x + 6 = 0
x(x - 3)(x + 1) + 2x(x - 3) - 2(x - 3) = 0
(x - 3)[x(x + 1) + 2x - 2] = 0
(x - 3)(x² + x + 2x - 2) = 0
(x - 3)(x² + 3x - 2) = 0
x - 3 = 0   ou  x² + 3x - 2 = 0
  
*) x - 3 = 0  
x = 3


*) x² + 3x - 2 = 0
Delta = 3² - 4*1*(-2) = 9 + 8 = 17
x_1=\dfrac{-3-\sqrt{17}}{2}\\\\x_2=\dfrac{-3+\sqrt{17}}{2}



D'où  :  S=\{3;\dfrac{-3-\sqrt{17}}{2};\dfrac{-3+\sqrt{17}}{2}\}