Réponses

2013-12-19T11:54:03+01:00
 (x+1)^3-(x+1)²=0 
(x+1)^3-2=0
(x+1)^1=0
x=-1
On vérifie:
(-1+1)³ - (-1+1)²= 0³-0²=0
2013-12-19T12:04:09+01:00
(x+1)^3-(x+1)²=0  
x^3 + 3x² + 3x +1 - x² -2x -1=0
x^3 + 2x² +x=0
x (x²+2x+1) = 0
x (x+1)² = 0
admet 2 solutions :
1) x=0    et
x+1 = 0
2) x = -1