Réponses

2013-12-05T10:40:52+01:00
2i(i+1)+2i(2+i)  = 2 i^2 + 2i + 4i + 2 i^2 = 4 i^2 + 6i = 2 i (2i +3)
2 solutions:
i = 0
2i+3 = 0  et i = -3/2
2013-12-05T11:30:39+01:00
Résoudre : 2i(i+1)+2i(2+i) =

2i (i + 1) + 2i (2 + i)  = 2i ^ 2 + 2i + 4i + 2i ^ 2 = 4i ^ 2 + 6i = 2 i (2i +3)
2i + 3 = 0 
d'où : i = -3/2