Réponses

2013-11-11T17:49:30+01:00
Bonsoir
0.1x²+0.12x+0.4 = 0.8x
0.1x²+0.12x+0.4 - 0.8x = 0
0.1x² -0.68x + 0.4 = 0 
delta = 0.3024
Vdelta = 0.5499 
deux solutions
x' = -0.6505 
x" = 6.1495 
c'est koi le delta =0.3024
vous etes sur de se resultat
Delta= b²-4ac = (0.68)²-4(0.1) (0.4) = 0.3024 racine de delta = 0.5499 deux solutions x' = (-b-Vdelta)2a = (0.68-0.5499)/0.2 = 0.6505 et x" = (-b+Vdelta)2a = (0.68+0.5499)0.2 = 6.1495
merci mec
vérification 0.1(6.1495)²-0.68(6.1495) +0.4 = 0 et 0.1(0.6505)²-0.68(0.6505)+0.4 = 0