Réponses

2013-11-02T16:37:56+01:00
2x-3 ≤ 2+4x => 2x >= -5 => x >= -5/2     S =  [-5/2 ; infini

3-5x ≥ 1+X => 6x <= 2 => x <= 1/3  S = -infini;  1/3]
(1-2x)² - 4x² > 0 => 1 + 4x² - 4x - 4x² > 0 => 1 - 4x > 0 => x < 1/4  S = -infini;1/4[