Réponses

2013-10-23T22:37:08+02:00
On a d'abord g(x) = (9 x + 5)/(3 x + 2) = (9 x + 6 - 1)/(3 x + 2) = (9 x + 6)/(3 x + 2) - 1/(3 x + 2) = 3 - 1/(3 x + 2) .
Ensuite on a : x > - 2/3 càd 3 x > - 2 càd 3 x + 2 > 0 càd 1/(3 x + 2) > 0 càd - 1/(3 x + 2) < 0 càd 3 - 1/(3 x + 2) < 3 càd g(x) < 3 .