Réponses

2013-04-14T23:24:24+02:00

(u/v)'=(u'v-v'u)/v²=

(u'v-v'u)=(8x-36)(x-12)-(1)*(4x²-36x)=8x²-36x-96x+432-(4x²-36x)=4x²-96x+432

v²=(x-12)²

On a donc 

(u/v)'=(u'v-v'u)/v²= 4x²-96x+432/(x-12)²