Réponses

2013-03-07T15:36:35+01:00

1) i=(3x-1)au carre-100=(3x) carre-2*3x*(-1)+(-1)caree-100=9x carree-5x+1-100=9xcarree-5x-99

2013-03-07T15:47:02+01:00
X=0
I=(3x0-1)^2-100 = -99
x=1
I = (3x1-1)^2-100 = -96
x=-2
i=(3x(-2)-1)^2-100= -51
x=3
I=(3x3-1)^2-100=-36