Réponses

2014-10-05T14:52:42+02:00
(3x-1)/5=(x+1)/2 ⇔(3x-3)/5-(x+1)/2=0 ⇔(6x-6-(5x+5))/10=0 ⇔(6x-6-5x-5)/10=0 ⇔x-11/10=0 ⇔x-11=0 ⇔x=11