Réponses

2014-09-17T13:33:27+02:00
C=(x+1)[6(3x-2)-2(2-5x)]=(x+1)[(18x-12)(-4-20x)]=(x+1)(18x-20x-4-12)=(x+1)(-2x-16)  D=16(x-1)(x-1)-8(x-1)(x+5)=(x-1)[(16x-16)(-8x-40)]=(x-1)(8x-56)
Mais c'est developper et non factoriser la non ?