3.9 kΩ = ...........Ω
5×10-³ A =...........mA
4.7μV = ..........Volt
6.8 MHz = ...........Hz
6800Ω = ............kΩ
1.2 km =........... m
10 000m = ......... hm
2.5 mA = ............A
3.7×10⁻⁶ V= .........μV
1.5× 10⁶Ω = ...........MΩ
1.5× 10⁻⁶ J= ..........μJ

1

Réponses

2014-09-12T19:42:03+02:00

3,9 kΩ = 3900 Ω
5×10-³ A = 5 mA
4.7μV = 4,7.10
⁻⁶ Volt
6.8 MHz = 6,8.10
⁷ Hz
6800Ω = 6,8 kΩ
1.2 km =1200  m
10 000m = 100 hm
2.5 mA = 2,5.10
⁻³ A
3.7×10⁻⁶ V= 3,7 μV
1.5× 10⁶Ω =1,5 MΩ
1.5× 10⁻⁶ J= 1,5 μJ
comment tu a fait pour trouver la 2eme réponse
10^-3 mA = 1A