Réponses

2014-04-10T09:31:52+02:00
A) V=Dr/t donc Dr=V*t
Dr=27,8*0,75=20,85m

b)  D_{F}= \frac{V^{2} }{2gA}=\frac{27,8^{2} }{2*9,81*0,6} =65,65m

V= \sqrt{2gA*D_{F} } =
V= \sqrt{2*9,81*0,4*65,65}=22,7 m. s^{-1} soit 81,7 km/h