Réponses

2014-02-27T21:56:33+01:00
F'(×) = 50.1/(e^(0,04×)+ 19) . 0,04 = 2/(e^(0,04×)+19)
2014-02-27T22:09:09+01:00
f'(×) = 50.1/(e^(0,04×)+ 19) . 0,04 = 2/(e^(0,04×)+19)