Réponses

2014-01-06T17:50:17+01:00
Rappel
Sin = coté opposé/ hypoténuse
cos = coté adjacent/hypoténuse
tan = coté opposé/coté adjacent
pour s'en souvenir dir SoCaToa = soh cah toa soh (s= sinus, o = coté opposé, h = hypoténuse, a= coté adjacent, c=cosinus, t= tangente)


I sin BAC = coté opposé/ hypoténuse = CB/CA = 8/10 = c
II cos BCA = coté adjacent/ hypoténuse = CB/CA = 8/10 = c
III cos BAC = coté adjacent/ hypoténuse = AB/CA = 6/10 = f
IV tan BAC = coté opposé/ coté adjacent = CB/AB = 8/6 = b
V sin BCA = coté opposé/ hypoténuse = AB/CA = 6/10 = f
VI tan BCA = coté opposé/ coté adjacent = BA/CB = 6/8 = a