Réponses

2013-12-17T18:55:00+01:00
E = 4x(x+3 )
F = x²+6x+9 
a) développer E   
E = 4x(x+3 ) 
=4x²+12x

b) réduire E - F 
=4x²+12x-(
x²+6x+9)
=4x²+12x-x²-6x-9
=3x²+6x-9

c) factoriser E + F
4x(x+3)+x²+6x+9 
=4x(x+3)+(x+3)²
=4x(x+3)+(x+3)(x+3)
=(x+3)(4x+x+3)
=(x+3)(5x+3)