Réponses

2013-09-08T08:18:27+02:00
C=3(4x-7)(7x+5)=3(28x^2+20x-49x-35)=3(28x^2-29x-35)=84x^2-87x-105

D=2x(-x-7)(10x+5)=(-2x^2-14x)(10x+5)=-20x^3-10x^2-140x^2-70x=-20x^3-150x^2-70x
2013-09-08T08:22:51+02:00
C= 3(4x-7)(7x+5)
3(28x² +20x -49x -35)
3(28x² -29x -35)
84x² -87x - 105

D=2x(-x-7)(10x+5)
2x ( -10x² -5x -70x -35)
2x (-10x² -75x -35)
-10x au cube -150x² -35x